Base | Representation |
---|---|
bin | 111101110111000000… |
… | …011001001110001011 |
3 | 20100110000000120000111 |
4 | 331313000121032023 |
5 | 2042012300221301 |
6 | 50302522415151 |
7 | 4540656022045 |
oct | 756700311613 |
9 | 210400016014 |
10 | 66421101451 |
11 | 26194a86681 |
12 | 10a583614b7 |
13 | 6356b450c3 |
14 | 330159aa95 |
15 | 1adb31b551 |
hex | f7701938b |
66421101451 has 4 divisors (see below), whose sum is σ = 66448314504. Its totient is φ = 66393888400.
The previous prime is 66421101401. The next prime is 66421101469. The reversal of 66421101451 is 15410112466.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 66421101451 - 27 = 66421101323 is a prime.
It is a Smith number, since the sum of its digits (31) coincides with the sum of the digits of its prime factors. Since it is squarefree, it is also a hoax number.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (66421101401) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13602865 + ... + 13607746.
It is an arithmetic number, because the mean of its divisors is an integer number (16612078626).
Almost surely, 266421101451 is an apocalyptic number.
66421101451 is a deficient number, since it is larger than the sum of its proper divisors (27213053).
66421101451 is a wasteful number, since it uses less digits than its factorization.
66421101451 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 27213052.
The product of its (nonzero) digits is 5760, while the sum is 31.
The spelling of 66421101451 in words is "sixty-six billion, four hundred twenty-one million, one hundred one thousand, four hundred fifty-one".
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