Base | Representation |
---|---|
bin | 10011010110111011101… |
… | …10110111111110111001 |
3 | 2100120212020122022110010 |
4 | 21223131312313332321 |
5 | 41344210130112101 |
6 | 1225321523012133 |
7 | 66024652115151 |
oct | 11533566677671 |
9 | 2316766568403 |
10 | 665147113401 |
11 | 2370a6229091 |
12 | a8ab050a049 |
13 | 4a952874314 |
14 | 2429c571761 |
15 | 1247e3d62d6 |
hex | 9adddb7fb9 |
665147113401 has 4 divisors (see below), whose sum is σ = 886862817872. Its totient is φ = 443431408932.
The previous prime is 665147113391. The next prime is 665147113439. The reversal of 665147113401 is 104311741566.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a de Polignac number, because none of the positive numbers 2k-665147113401 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is a self number, because there is not a number n which added to its sum of digits gives 665147113401.
It is not an unprimeable number, because it can be changed into a prime (665147113201) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 110857852231 + ... + 110857852236.
It is an arithmetic number, because the mean of its divisors is an integer number (221715704468).
Almost surely, 2665147113401 is an apocalyptic number.
It is an amenable number.
665147113401 is a deficient number, since it is larger than the sum of its proper divisors (221715704471).
665147113401 is a wasteful number, since it uses less digits than its factorization.
665147113401 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 221715704470.
The product of its (nonzero) digits is 60480, while the sum is 39.
Adding to 665147113401 its reverse (104311741566), we get a palindrome (769458854967).
The spelling of 665147113401 in words is "six hundred sixty-five billion, one hundred forty-seven million, one hundred thirteen thousand, four hundred one".
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