Base | Representation |
---|---|
bin | 11110010010100001010011… |
… | …10100100100011100110011 |
3 | 22201211120110011000111001212 |
4 | 33021100221310210130303 |
5 | 32212242221421114021 |
6 | 353354505225350335 |
7 | 20013125621351423 |
oct | 1711205164443463 |
9 | 281746404014055 |
10 | 66607054473011 |
11 | 1a24a990898038 |
12 | 7578a879383ab |
13 | 2b22031234a70 |
14 | 1263b27666483 |
15 | 7a7907d8285b |
hex | 3c9429d24733 |
66607054473011 has 4 divisors (see below), whose sum is σ = 71730674047872. Its totient is φ = 61483434898152.
The previous prime is 66607054472977. The next prime is 66607054473017. The reversal of 66607054473011 is 11037445070666.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 66607054473011 - 218 = 66607054210867 is a prime.
It is a super-2 number, since 2×666070544730112 (a number of 28 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (66607054473017) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2561809787411 + ... + 2561809787436.
It is an arithmetic number, because the mean of its divisors is an integer number (17932668511968).
Almost surely, 266607054473011 is an apocalyptic number.
66607054473011 is a deficient number, since it is larger than the sum of its proper divisors (5123619574861).
66607054473011 is a wasteful number, since it uses less digits than its factorization.
66607054473011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5123619574860.
The product of its (nonzero) digits is 2540160, while the sum is 50.
The spelling of 66607054473011 in words is "sixty-six trillion, six hundred seven billion, fifty-four million, four hundred seventy-three thousand, eleven".
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