Base | Representation |
---|---|
bin | 1100011011101111… |
… | …00010010111011001 |
3 | 122020012101220012110 |
4 | 12031313202113121 |
5 | 102132312112213 |
6 | 3022210502533 |
7 | 324262346052 |
oct | 61567422731 |
9 | 18205356173 |
10 | 6675113433 |
11 | 2915a2257a |
12 | 1363594a49 |
13 | 824c03781 |
14 | 474749729 |
15 | 2910415c3 |
hex | 18dde25d9 |
6675113433 has 16 divisors (see below), whose sum is σ = 8935405056. Its totient is φ = 4432471680.
The previous prime is 6675113387. The next prime is 6675113441. The reversal of 6675113433 is 3343115766.
6675113433 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 6675113433 - 28 = 6675113177 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 6675113391 and 6675113400.
It is not an unprimeable number, because it can be changed into a prime (6675113033) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2070763 + ... + 2073983.
It is an arithmetic number, because the mean of its divisors is an integer number (558462816).
Almost surely, 26675113433 is an apocalyptic number.
It is an amenable number.
6675113433 is a deficient number, since it is larger than the sum of its proper divisors (2260291623).
6675113433 is a wasteful number, since it uses less digits than its factorization.
6675113433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5744.
The product of its digits is 136080, while the sum is 39.
The square root of 6675113433 is about 81701.3673875780. The cubic root of 6675113433 is about 1882.8665934383.
The spelling of 6675113433 in words is "six billion, six hundred seventy-five million, one hundred thirteen thousand, four hundred thirty-three".
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