Base | Representation |
---|---|
bin | 111110010100010011… |
… | …100011011001001001 |
3 | 20101201020222110211222 |
4 | 332110103203121021 |
5 | 2044014120204423 |
6 | 50423402331425 |
7 | 4556105152322 |
oct | 762423433111 |
9 | 211636873758 |
10 | 66912663113 |
11 | 264174aa18a |
12 | 10b74ab9b75 |
13 | 64049343aa |
14 | 334a997449 |
15 | 1b195693c8 |
hex | f944e3649 |
66912663113 has 4 divisors (see below), whose sum is σ = 66913212288. Its totient is φ = 66912113940.
The previous prime is 66912662981. The next prime is 66912663121. The reversal of 66912663113 is 31136621966.
66912663113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.
It is a cyclic number.
It is not a de Polignac number, because 66912663113 - 28 = 66912662857 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (66912663133) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 881 + ... + 365822.
It is an arithmetic number, because the mean of its divisors is an integer number (16728303072).
Almost surely, 266912663113 is an apocalyptic number.
It is an amenable number.
66912663113 is a deficient number, since it is larger than the sum of its proper divisors (549175).
66912663113 is a wasteful number, since it uses less digits than its factorization.
66912663113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 549174.
The product of its digits is 209952, while the sum is 44.
The spelling of 66912663113 in words is "sixty-six billion, nine hundred twelve million, six hundred sixty-three thousand, one hundred thirteen".
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