Base | Representation |
---|---|
bin | 110001011111000110000… |
… | …0101001101100000110001 |
3 | 220002012022010122001202201 |
4 | 1202332030011031200301 |
5 | 1342413012022441443 |
6 | 22244244431143201 |
7 | 1301243100041245 |
oct | 142761405154061 |
9 | 26065263561681 |
10 | 6801283405873 |
11 | 219245419aa60 |
12 | 91a174074b01 |
13 | 3a4487184318 |
14 | 197280796425 |
15 | bbdb4c8d34d |
hex | 62f8c14d831 |
6801283405873 has 16 divisors (see below), whose sum is σ = 7622408557440. Its totient is φ = 6014063462400.
The previous prime is 6801283405867. The next prime is 6801283405967. The reversal of 6801283405873 is 3785043821086.
It is a cyclic number.
It is not a de Polignac number, because 6801283405873 - 229 = 6800746534961 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (6801283409873) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1166608 + ... + 3868273.
It is an arithmetic number, because the mean of its divisors is an integer number (476400534840).
Almost surely, 26801283405873 is an apocalyptic number.
It is an amenable number.
6801283405873 is a deficient number, since it is larger than the sum of its proper divisors (821125151567).
6801283405873 is a wasteful number, since it uses less digits than its factorization.
6801283405873 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5038248.
The product of its (nonzero) digits is 7741440, while the sum is 55.
The spelling of 6801283405873 in words is "six trillion, eight hundred one billion, two hundred eighty-three million, four hundred five thousand, eight hundred seventy-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.075 sec. • engine limits •