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682113 = 3227371
BaseRepresentation
bin10100110100010000001
31021122200110
42212202001
5133311423
622341533
75540445
oct2464201
91248613
10682113
11426533
1228a8a9
131ab623
1413a825
15d7193
hexa6881

682113 has 4 divisors (see below), whose sum is σ = 909488. Its totient is φ = 454740.

The previous prime is 682079. The next prime is 682141. The reversal of 682113 is 311286.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 682113 - 26 = 682049 is a prime.

It is an Ulam number.

It is a D-number.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 682113.

It is not an unprimeable number, because it can be changed into a prime (682153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (7) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 113683 + ... + 113688.

It is an arithmetic number, because the mean of its divisors is an integer number (227372).

2682113 is an apocalyptic number.

It is an amenable number.

682113 is a deficient number, since it is larger than the sum of its proper divisors (227375).

682113 is a wasteful number, since it uses less digits than its factorization.

682113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 227374.

The product of its digits is 288, while the sum is 21.

The square root of 682113 is about 825.9013258253. The cubic root of 682113 is about 88.0275826071.

Adding to 682113 its reverse (311286), we get a palindrome (993399).

The spelling of 682113 in words is "six hundred eighty-two thousand, one hundred thirteen".

Divisors: 1 3 227371 682113