Base | Representation |
---|---|
bin | 111111101001011100… |
… | …101110110011111001 |
3 | 20112101210220020111221 |
4 | 333221130232303321 |
5 | 2104430312220122 |
6 | 51221231352041 |
7 | 4636362020236 |
oct | 775134566371 |
9 | 215353806457 |
10 | 68341132537 |
11 | 26a8a873427 |
12 | 112b3382621 |
13 | 65a1870282 |
14 | 344459a78d |
15 | 1b9eb846c7 |
hex | fe972ecf9 |
68341132537 has 8 divisors (see below), whose sum is σ = 69285696480. Its totient is φ = 67399453920.
The previous prime is 68341132529. The next prime is 68341132549. The reversal of 68341132537 is 73523114386.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 68341132537 - 23 = 68341132529 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 68341132493 and 68341132502.
It is not an unprimeable number, because it can be changed into a prime (68341102537) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 673612 + ... + 768397.
It is an arithmetic number, because the mean of its divisors is an integer number (8660712060).
Almost surely, 268341132537 is an apocalyptic number.
It is an amenable number.
68341132537 is a deficient number, since it is larger than the sum of its proper divisors (944563943).
68341132537 is a wasteful number, since it uses less digits than its factorization.
68341132537 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1442663.
The product of its digits is 362880, while the sum is 43.
The spelling of 68341132537 in words is "sixty-eight billion, three hundred forty-one million, one hundred thirty-two thousand, five hundred thirty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.074 sec. • engine limits •