Base | Representation |
---|---|
bin | 100000000000101001… |
… | …1101110101001010011 |
3 | 20120102201010020120101 |
4 | 1000001103232221103 |
5 | 2111240301110442 |
6 | 51325051153231 |
7 | 4652322322651 |
oct | 1000123565123 |
9 | 216381106511 |
10 | 68741425747 |
11 | 27175819665 |
12 | 113a5445817 |
13 | 6636785167 |
14 | 34817d9dd1 |
15 | 1bc4da4cb7 |
hex | 10014eea53 |
68741425747 has 4 divisors (see below), whose sum is σ = 68750918496. Its totient is φ = 68731933000.
The previous prime is 68741425733. The next prime is 68741425751. The reversal of 68741425747 is 74752414786.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 68741425747 - 27 = 68741425619 is a prime.
It is a super-3 number, since 3×687414257473 (a number of 33 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (68741425147) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4735504 + ... + 4749997.
It is an arithmetic number, because the mean of its divisors is an integer number (17187729624).
Almost surely, 268741425747 is an apocalyptic number.
68741425747 is a deficient number, since it is larger than the sum of its proper divisors (9492749).
68741425747 is an equidigital number, since it uses as much as digits as its factorization.
68741425747 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 9492748.
The product of its digits is 10536960, while the sum is 55.
The spelling of 68741425747 in words is "sixty-eight billion, seven hundred forty-one million, four hundred twenty-five thousand, seven hundred forty-seven".
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