Base | Representation |
---|---|
bin | 110010011111111100100… |
… | …1101101010011001010001 |
3 | 220120111210002111021200002 |
4 | 1210333321031222121101 |
5 | 1402203223120310340 |
6 | 22432240212135345 |
7 | 1314303244402622 |
oct | 144777115523121 |
9 | 26514702437602 |
10 | 6940553291345 |
11 | 2236521436263 |
12 | 941161307555 |
13 | 3b46506c1a8b |
14 | 19dcd304ba49 |
15 | c081683e715 |
hex | 64ff936a651 |
6940553291345 has 4 divisors (see below), whose sum is σ = 8328663949620. Its totient is φ = 5552442633072.
The previous prime is 6940553291341. The next prime is 6940553291369. The reversal of 6940553291345 is 5431923550496.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 3663732871744 + 3276820419601 = 1914088^2 + 1810199^2 .
It is a cyclic number.
It is not a de Polignac number, because 6940553291345 - 22 = 6940553291341 is a prime.
It is not an unprimeable number, because it can be changed into a prime (6940553291341) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 694055329130 + ... + 694055329139.
It is an arithmetic number, because the mean of its divisors is an integer number (2082165987405).
Almost surely, 26940553291345 is an apocalyptic number.
It is an amenable number.
6940553291345 is a deficient number, since it is larger than the sum of its proper divisors (1388110658275).
6940553291345 is a wasteful number, since it uses less digits than its factorization.
6940553291345 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1388110658274.
The product of its (nonzero) digits is 17496000, while the sum is 56.
The spelling of 6940553291345 in words is "six trillion, nine hundred forty billion, five hundred fifty-three million, two hundred ninety-one thousand, three hundred forty-five".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •