Base | Representation |
---|---|
bin | 100000100101101011… |
… | …1110001100000000011 |
3 | 20200122022020120000010 |
4 | 1001023113301200003 |
5 | 2121311401000003 |
6 | 52052240000003 |
7 | 5025161120301 |
oct | 1011327614003 |
9 | 220568216003 |
10 | 69984000003 |
11 | 27753164035 |
12 | 11691600003 |
13 | 67a4034ab8 |
14 | 355c84d271 |
15 | 1c49000003 |
hex | 104b5f1803 |
69984000003 has 8 divisors (see below), whose sum is σ = 93499000000. Its totient is φ = 46562500008.
The previous prime is 69984000001. The next prime is 69984000013. The reversal of 69984000003 is 30000048996.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 69984000003 - 21 = 69984000001 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (69984000001) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 23373253 + ... + 23376246.
It is an arithmetic number, because the mean of its divisors is an integer number (11687375000).
Almost surely, 269984000003 is an apocalyptic number.
69984000003 is a deficient number, since it is larger than the sum of its proper divisors (23514999997).
69984000003 is a wasteful number, since it uses less digits than its factorization.
69984000003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 46750001.
The product of its (nonzero) digits is 46656, while the sum is 39.
Adding to 69984000003 its reverse (30000048996), we get a palindrome (99984048999).
The spelling of 69984000003 in words is "sixty-nine billion, nine hundred eighty-four million, three", and thus it is an aban number.
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