Base | Representation |
---|---|
bin | 100000100101111110… |
… | …1111110001000111011 |
3 | 20200200000002021120212 |
4 | 1001023331332020323 |
5 | 2121321431410433 |
6 | 52053234341335 |
7 | 5025342203360 |
oct | 1011375761073 |
9 | 220600067525 |
10 | 69994013243 |
11 | 27758883140 |
12 | 11694a2a84b |
13 | 67a612c6ab |
14 | 355dcd8467 |
15 | 1c49d2bd48 |
hex | 104bf7e23b |
69994013243 has 16 divisors (see below), whose sum is σ = 88245780480. Its totient is φ = 53927966400.
The previous prime is 69994013239. The next prime is 69994013273. The reversal of 69994013243 is 34231049996.
It is not a de Polignac number, because 69994013243 - 22 = 69994013239 is a prime.
It is a super-2 number, since 2×699940132432 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 69994013191 and 69994013200.
It is not an unprimeable number, because it can be changed into a prime (69994013273) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5099963 + ... + 5113668.
It is an arithmetic number, because the mean of its divisors is an integer number (5515361280).
Almost surely, 269994013243 is an apocalyptic number.
69994013243 is a deficient number, since it is larger than the sum of its proper divisors (18251767237).
69994013243 is a wasteful number, since it uses less digits than its factorization.
69994013243 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10213738.
The product of its (nonzero) digits is 1259712, while the sum is 50.
The spelling of 69994013243 in words is "sixty-nine billion, nine hundred ninety-four million, thirteen thousand, two hundred forty-three".
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