Base | Representation |
---|---|
bin | 110011111011111100100… |
… | …1100101110111100001001 |
3 | 221021101201222000101011000 |
4 | 1213313321030232330021 |
5 | 1413422333103342213 |
6 | 23103112513325213 |
7 | 1334466210004566 |
oct | 147677114567411 |
9 | 27241658011130 |
10 | 7138121543433 |
11 | 2302295580241 |
12 | 9734ba566809 |
13 | 3ca177c8a85a |
14 | 1a96b61a786d |
15 | c5a2b56ac73 |
hex | 67df932ef09 |
7138121543433 has 16 divisors (see below), whose sum is σ = 10575237703360. Its totient is φ = 4758638424768.
The previous prime is 7138121543417. The next prime is 7138121543447. The reversal of 7138121543433 is 3343451218317.
7138121543433 is a `hidden beast` number, since 7 + 1 + 3 + 81 + 21 + 543 + 4 + 3 + 3 = 666.
It is not a de Polignac number, because 7138121543433 - 24 = 7138121543417 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (7138121543933) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1828960 + ... + 4197777.
It is an arithmetic number, because the mean of its divisors is an integer number (660952356460).
Almost surely, 27138121543433 is an apocalyptic number.
It is an amenable number.
7138121543433 is a deficient number, since it is larger than the sum of its proper divisors (3437116159927).
7138121543433 is a wasteful number, since it uses less digits than its factorization.
7138121543433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6070613 (or 6070607 counting only the distinct ones).
The product of its digits is 725760, while the sum is 45.
The spelling of 7138121543433 in words is "seven trillion, one hundred thirty-eight billion, one hundred twenty-one million, five hundred forty-three thousand, four hundred thirty-three".
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