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71489345833 = 107057667769
BaseRepresentation
bin100001010010100011…
…0001101100100101001
320211112012211001021101
41002211012031210221
52132402233031313
652501452441401
75110400261533
oct1024506154451
9224465731241
1071489345833
11283559656a4
1211a31779261
136983b79389
143662744853
151cd62535dd
hex10a518d929

71489345833 has 4 divisors (see below), whose sum is σ = 71490120660. Its totient is φ = 71488571008.

The previous prime is 71489345827. The next prime is 71489345887. The reversal of 71489345833 is 33854398417.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It can be written as a sum of positive squares in 2 ways, for example, as 45210666384 + 26278679449 = 212628^2 + 162107^2 .

It is a cyclic number.

It is not a de Polignac number, because 71489345833 - 25 = 71489345801 is a prime.

It is a super-2 number, since 2×714893458332 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (71489345813) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 226828 + ... + 440941.

It is an arithmetic number, because the mean of its divisors is an integer number (17872530165).

Almost surely, 271489345833 is an apocalyptic number.

It is an amenable number.

71489345833 is a deficient number, since it is larger than the sum of its proper divisors (774827).

71489345833 is a wasteful number, since it uses less digits than its factorization.

71489345833 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 774826.

The product of its digits is 8709120, while the sum is 55.

The spelling of 71489345833 in words is "seventy-one billion, four hundred eighty-nine million, three hundred forty-five thousand, eight hundred thirty-three".

Divisors: 1 107057 667769 71489345833