Base | Representation |
---|---|
bin | 110101111100010100100… |
… | …1010001010011111001011 |
3 | 222020202022202100102112212 |
4 | 1223320221022022133023 |
5 | 1432431432321130042 |
6 | 23433504331055335 |
7 | 1363425655636460 |
oct | 153705112123713 |
9 | 28222282312485 |
10 | 7413804083147 |
11 | 23a91a4144720 |
12 | 9b8a17ba154b |
13 | 41a170ababb7 |
14 | 1b8b89873667 |
15 | cccb3e2b482 |
hex | 6be2928a7cb |
7413804083147 has 16 divisors (see below), whose sum is σ = 9248518109952. Its totient is φ = 5773656570720.
The previous prime is 7413804083137. The next prime is 7413804083207.
7413804083147 is nontrivially palindromic in base 10.
It is a cyclic number.
It is not a de Polignac number, because 7413804083147 - 24 = 7413804083131 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 7413804083095 and 7413804083104.
It is not an unprimeable number, because it can be changed into a prime (7413804083117) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 27645893 + ... + 27912774.
It is an arithmetic number, because the mean of its divisors is an integer number (578032381872).
Almost surely, 27413804083147 is an apocalyptic number.
7413804083147 is a gapful number since it is divisible by the number (77) formed by its first and last digit.
7413804083147 is a deficient number, since it is larger than the sum of its proper divisors (1834714026805).
7413804083147 is a wasteful number, since it uses less digits than its factorization.
7413804083147 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 55560418.
The product of its (nonzero) digits is 1806336, while the sum is 50.
The spelling of 7413804083147 in words is "seven trillion, four hundred thirteen billion, eight hundred four million, eighty-three thousand, one hundred forty-seven".
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