Base | Representation |
---|---|
bin | 100010100001100000… |
… | …0101000011100001011 |
3 | 21002100212000022211121 |
4 | 1011003000220130023 |
5 | 2203314000330042 |
6 | 54020413140111 |
7 | 5233140260164 |
oct | 1050300503413 |
9 | 232325008747 |
10 | 74138683147 |
11 | 29495398a71 |
12 | 12450a8a637 |
13 | 6cb6a04ba9 |
14 | 383454a76b |
15 | 1dddb2c367 |
hex | 114302870b |
74138683147 has 4 divisors (see below), whose sum is σ = 74362667416. Its totient is φ = 73914698880.
The previous prime is 74138683139. The next prime is 74138683169.
74138683147 is nontrivially palindromic in base 10.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 74138683147 - 23 = 74138683139 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 74138683094 and 74138683103.
It is not an unprimeable number, because it can be changed into a prime (74138683747) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 111991638 + ... + 111992299.
It is an arithmetic number, because the mean of its divisors is an integer number (18590666854).
Almost surely, 274138683147 is an apocalyptic number.
74138683147 is a deficient number, since it is larger than the sum of its proper divisors (223984269).
74138683147 is a wasteful number, since it uses less digits than its factorization.
74138683147 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 223984268.
The product of its digits is 2709504, while the sum is 52.
The spelling of 74138683147 in words is "seventy-four billion, one hundred thirty-eight million, six hundred eighty-three thousand, one hundred forty-seven".
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