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79131455113 = 194164813427
BaseRepresentation
bin100100110110010011…
…0100010111010001001
321120020210210102101211
41021230212202322021
52244030123030423
6100204045413121
75500644161524
oct1115446427211
9246223712354
1079131455113
1130617709497
1213404b6a1a1
137601202829
143b89689bbb
1520d210710d
hex126c9a2e89

79131455113 has 4 divisors (see below), whose sum is σ = 83296268560. Its totient is φ = 74966641668.

The previous prime is 79131455093. The next prime is 79131455147. The reversal of 79131455113 is 31155413197.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 79131455113 - 29 = 79131454601 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (79131455713) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2082406695 + ... + 2082406732.

It is an arithmetic number, because the mean of its divisors is an integer number (20824067140).

Almost surely, 279131455113 is an apocalyptic number.

It is an amenable number.

79131455113 is a deficient number, since it is larger than the sum of its proper divisors (4164813447).

79131455113 is a wasteful number, since it uses less digits than its factorization.

79131455113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4164813446.

The product of its digits is 56700, while the sum is 40.

The spelling of 79131455113 in words is "seventy-nine billion, one hundred thirty-one million, four hundred fifty-five thousand, one hundred thirteen".

Divisors: 1 19 4164813427 79131455113