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79421350030115 = 579201066708937
BaseRepresentation
bin10010000011101110111001…
…010110110010101100100011
3101102012121101102211212112212
4102003232321112302230203
540402214411101430430
6440525355311312335
722505001043411142
oct2203567126625443
9342177342755485
1079421350030115
1123340450644235
128aa848151b6ab
13354152a4b3632
14158802a01b759
1592ade910ab95
hex483bb95b2b23

79421350030115 has 8 divisors (see below), whose sum is σ = 96512020290240. Its totient is φ = 62732813188032.

The previous prime is 79421350030081. The next prime is 79421350030159. The reversal of 79421350030115 is 51103005312497.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 79421350030115 - 232 = 79417055062819 is a prime.

It is a super-2 number, since 2×794213500301152 (a number of 29 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 100533354074 + ... + 100533354863.

It is an arithmetic number, because the mean of its divisors is an integer number (12064002536280).

Almost surely, 279421350030115 is an apocalyptic number.

79421350030115 is a deficient number, since it is larger than the sum of its proper divisors (17090670260125).

79421350030115 is a wasteful number, since it uses less digits than its factorization.

79421350030115 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 201066709021.

The product of its (nonzero) digits is 113400, while the sum is 41.

The spelling of 79421350030115 in words is "seventy-nine trillion, four hundred twenty-one billion, three hundred fifty million, thirty thousand, one hundred fifteen".

Divisors: 1 5 79 395 201066708937 1005333544685 15884270006023 79421350030115