Base | Representation |
---|---|
bin | 10010000011101110111001… |
… | …010110110010101100100011 |
3 | 101102012121101102211212112212 |
4 | 102003232321112302230203 |
5 | 40402214411101430430 |
6 | 440525355311312335 |
7 | 22505001043411142 |
oct | 2203567126625443 |
9 | 342177342755485 |
10 | 79421350030115 |
11 | 23340450644235 |
12 | 8aa848151b6ab |
13 | 354152a4b3632 |
14 | 158802a01b759 |
15 | 92ade910ab95 |
hex | 483bb95b2b23 |
79421350030115 has 8 divisors (see below), whose sum is σ = 96512020290240. Its totient is φ = 62732813188032.
The previous prime is 79421350030081. The next prime is 79421350030159. The reversal of 79421350030115 is 51103005312497.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 79421350030115 - 232 = 79417055062819 is a prime.
It is a super-2 number, since 2×794213500301152 (a number of 29 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 100533354074 + ... + 100533354863.
It is an arithmetic number, because the mean of its divisors is an integer number (12064002536280).
Almost surely, 279421350030115 is an apocalyptic number.
79421350030115 is a deficient number, since it is larger than the sum of its proper divisors (17090670260125).
79421350030115 is a wasteful number, since it uses less digits than its factorization.
79421350030115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 201066709021.
The product of its (nonzero) digits is 113400, while the sum is 41.
The spelling of 79421350030115 in words is "seventy-nine trillion, four hundred twenty-one billion, three hundred fifty million, thirty thousand, one hundred fifteen".
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