Base | Representation |
---|---|
bin | 100101001111111111… |
… | …0101010001000000011 |
3 | 21122110212201110220111 |
4 | 1022133332222020003 |
5 | 2302311303223042 |
6 | 100425400252151 |
7 | 5531211541603 |
oct | 1123776521003 |
9 | 248425643814 |
10 | 79993414147 |
11 | 30a1a219029 |
12 | 13605771057 |
13 | 770a96a26a |
14 | 3c2bd42c03 |
15 | 2132b1c517 |
hex | 129ffaa203 |
79993414147 has 4 divisors (see below), whose sum is σ = 79994191600. Its totient is φ = 79992636696.
The previous prime is 79993414093. The next prime is 79993414229. The reversal of 79993414147 is 74141439997.
It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-79993414147 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 79993414091 and 79993414100.
It is not an unprimeable number, because it can be changed into a prime (79993414247) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 205647 + ... + 449752.
It is an arithmetic number, because the mean of its divisors is an integer number (19998547900).
Almost surely, 279993414147 is an apocalyptic number.
79993414147 is a deficient number, since it is larger than the sum of its proper divisors (777453).
79993414147 is a wasteful number, since it uses less digits than its factorization.
79993414147 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 777452.
The product of its digits is 6858432, while the sum is 58.
The spelling of 79993414147 in words is "seventy-nine billion, nine hundred ninety-three million, four hundred fourteen thousand, one hundred forty-seven".
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