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80042955433 = 711434707919
BaseRepresentation
bin100101010001011101…
…1101001001010101001
321122121022221102202221
41022202323221022221
52302411444033213
6100434330154041
75532352616050
oct1124273511251
9248538842687
1080042955433
1130a45186141
121361a282921
137717cc492c
143c3475b397
15213715638d
hex12a2ee92a9

80042955433 has 4 divisors (see below), whose sum is σ = 91477663360. Its totient is φ = 68608247508.

The previous prime is 80042955401. The next prime is 80042955449. The reversal of 80042955433 is 33455924008.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 80042955433 - 25 = 80042955401 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 80042955433.

It is not an unprimeable number, because it can be changed into a prime (80042952433) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5717353953 + ... + 5717353966.

It is an arithmetic number, because the mean of its divisors is an integer number (22869415840).

Almost surely, 280042955433 is an apocalyptic number.

It is an amenable number.

80042955433 is a deficient number, since it is larger than the sum of its proper divisors (11434707927).

80042955433 is a wasteful number, since it uses less digits than its factorization.

80042955433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11434707926.

The product of its (nonzero) digits is 518400, while the sum is 43.

The spelling of 80042955433 in words is "eighty billion, forty-two million, nine hundred fifty-five thousand, four hundred thirty-three".

Divisors: 1 7 11434707919 80042955433