Base | Representation |
---|---|
bin | 10010010000101110010010… |
… | …011011001000101001001011 |
3 | 101112100221121020102210010112 |
4 | 102100232102123020221023 |
5 | 41011331133303222411 |
6 | 442451433143104535 |
7 | 22626333013414463 |
oct | 2220562233105113 |
9 | 345327536383115 |
10 | 80314050054731 |
11 | 23654aa7522519 |
12 | 9011498a4214b |
13 | 35a7775776c7c |
14 | 15b9313abcba3 |
15 | 944245816b8b |
hex | 490b926c8a4b |
80314050054731 has 4 divisors (see below), whose sum is σ = 80355215638464. Its totient is φ = 80272884471000.
The previous prime is 80314050054671. The next prime is 80314050054737. The reversal of 80314050054731 is 13745005041308.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-80314050054731 is a prime.
It is a super-2 number, since 2×803140500547312 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (80314050054737) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20582788940 + ... + 20582792841.
It is an arithmetic number, because the mean of its divisors is an integer number (20088803909616).
Almost surely, 280314050054731 is an apocalyptic number.
80314050054731 is a deficient number, since it is larger than the sum of its proper divisors (41165583733).
80314050054731 is a wasteful number, since it uses less digits than its factorization.
80314050054731 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 41165583732.
The product of its (nonzero) digits is 201600, while the sum is 41.
The spelling of 80314050054731 in words is "eighty trillion, three hundred fourteen billion, fifty million, fifty-four thousand, seven hundred thirty-one".
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