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80314050054731 = 195141165581781
BaseRepresentation
bin10010010000101110010010…
…011011001000101001001011
3101112100221121020102210010112
4102100232102123020221023
541011331133303222411
6442451433143104535
722626333013414463
oct2220562233105113
9345327536383115
1080314050054731
1123654aa7522519
129011498a4214b
1335a7775776c7c
1415b9313abcba3
15944245816b8b
hex490b926c8a4b

80314050054731 has 4 divisors (see below), whose sum is σ = 80355215638464. Its totient is φ = 80272884471000.

The previous prime is 80314050054671. The next prime is 80314050054737. The reversal of 80314050054731 is 13745005041308.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-80314050054731 is a prime.

It is a super-2 number, since 2×803140500547312 (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (80314050054737) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20582788940 + ... + 20582792841.

It is an arithmetic number, because the mean of its divisors is an integer number (20088803909616).

Almost surely, 280314050054731 is an apocalyptic number.

80314050054731 is a deficient number, since it is larger than the sum of its proper divisors (41165583733).

80314050054731 is a wasteful number, since it uses less digits than its factorization.

80314050054731 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 41165583732.

The product of its (nonzero) digits is 201600, while the sum is 41.

The spelling of 80314050054731 in words is "eighty trillion, three hundred fourteen billion, fifty million, fifty-four thousand, seven hundred thirty-one".

Divisors: 1 1951 41165581781 80314050054731