Base | Representation |
---|---|
bin | 10111011001110001001… |
… | …10110011111001010011 |
3 | 2211212112201011100121020 |
4 | 23230320212303321103 |
5 | 101133303244114413 |
6 | 1413222525330523 |
7 | 112044363114423 |
oct | 13547046637123 |
9 | 2755481140536 |
10 | 804108582483 |
11 | 290025371608 |
12 | 10ba12406a43 |
13 | 5aa9a22817b |
14 | 2acc1ca2483 |
15 | 15db3d64c23 |
hex | bb389b3e53 |
804108582483 has 4 divisors (see below), whose sum is σ = 1072144776648. Its totient is φ = 536072388320.
The previous prime is 804108582481. The next prime is 804108582539. The reversal of 804108582483 is 384285801408.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 804108582483 - 21 = 804108582481 is a prime.
It is a super-2 number, since 2×8041085824832 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (804108582481) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 134018097078 + ... + 134018097083.
It is an arithmetic number, because the mean of its divisors is an integer number (268036194162).
Almost surely, 2804108582483 is an apocalyptic number.
804108582483 is a deficient number, since it is larger than the sum of its proper divisors (268036194165).
804108582483 is a wasteful number, since it uses less digits than its factorization.
804108582483 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 268036194164.
The product of its (nonzero) digits is 1966080, while the sum is 51.
The spelling of 804108582483 in words is "eight hundred four billion, one hundred eight million, five hundred eighty-two thousand, four hundred eighty-three".
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