Base | Representation |
---|---|
bin | 100101110001101010… |
… | …1010011110001111011 |
3 | 21202101122000222221020 |
4 | 1023203111103301323 |
5 | 2312120044103103 |
6 | 101133444313523 |
7 | 5601212511216 |
oct | 1134325236173 |
9 | 252348028836 |
10 | 81123425403 |
11 | 3144a071229 |
12 | 138800a28a3 |
13 | 785aac8087 |
14 | 3cd805477d |
15 | 219be30753 |
hex | 12e3553c7b |
81123425403 has 8 divisors (see below), whose sum is σ = 108167400000. Its totient is φ = 54080867208.
The previous prime is 81123425399. The next prime is 81123425423. The reversal of 81123425403 is 30452432118.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 81123425403 - 22 = 81123425399 is a prime.
It is a super-2 number, since 2×811234254032 (a number of 23 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (81123425423) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 212353 + ... + 455346.
It is an arithmetic number, because the mean of its divisors is an integer number (13520925000).
Almost surely, 281123425403 is an apocalyptic number.
81123425403 is a deficient number, since it is larger than the sum of its proper divisors (27043974597).
81123425403 is a wasteful number, since it uses less digits than its factorization.
81123425403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 708201.
The product of its (nonzero) digits is 23040, while the sum is 33.
The spelling of 81123425403 in words is "eighty-one billion, one hundred twenty-three million, four hundred twenty-five thousand, four hundred three".
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