Base | Representation |
---|---|
bin | 10111100111100100001… |
… | …00000001111010110011 |
3 | 2212120122212122001200001 |
4 | 23303302010001322303 |
5 | 101243440314304410 |
6 | 1420445502410431 |
7 | 112426045432102 |
oct | 13636204017263 |
9 | 2776585561601 |
10 | 811514994355 |
11 | 29318607045a |
12 | 11133a890a17 |
13 | 5b6aa7a8cc0 |
14 | 2b3c57b2039 |
15 | 161991ac33a |
hex | bcf2101eb3 |
811514994355 has 16 divisors (see below), whose sum is σ = 1048879266624. Its totient is φ = 599185641600.
The previous prime is 811514994349. The next prime is 811514994361. The reversal of 811514994355 is 553499415118.
811514994355 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is an interprime number because it is at equal distance from previous prime (811514994349) and next prime (811514994361).
It is not a de Polignac number, because 811514994355 - 211 = 811514992307 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 811514994296 and 811514994305.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 452871 + ... + 1352080.
It is an arithmetic number, because the mean of its divisors is an integer number (65554954164).
Almost surely, 2811514994355 is an apocalyptic number.
811514994355 is a deficient number, since it is larger than the sum of its proper divisors (237364272269).
811514994355 is a wasteful number, since it uses less digits than its factorization.
811514994355 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1811886.
The product of its digits is 3888000, while the sum is 55.
The spelling of 811514994355 in words is "eight hundred eleven billion, five hundred fourteen million, nine hundred ninety-four thousand, three hundred fifty-five".
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