Base | Representation |
---|---|
bin | 10010110101011000101010… |
… | …000010111011000111000011 |
3 | 101212021210121011220101202101 |
4 | 102311120222002323013003 |
5 | 41324120343314231011 |
6 | 452101054213331231 |
7 | 23306342656403455 |
oct | 2265305202730703 |
9 | 355253534811671 |
10 | 82833444680131 |
11 | 24436515070932 |
12 | 9359815036b17 |
13 | 372b2112a59c2 |
14 | 16652354d22d5 |
15 | 989a4be632c1 |
hex | 4b562a0bb1c3 |
82833444680131 has 4 divisors (see below), whose sum is σ = 82844446606200. Its totient is φ = 82822442754064.
The previous prime is 82833444680113. The next prime is 82833444680143. The reversal of 82833444680131 is 13108644433828.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 82833444680131 - 215 = 82833444647363 is a prime.
It is a super-2 number, since 2×828334446801312 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (82833444680111) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5500951741 + ... + 5500966798.
It is an arithmetic number, because the mean of its divisors is an integer number (20711111651550).
Almost surely, 282833444680131 is an apocalyptic number.
82833444680131 is a deficient number, since it is larger than the sum of its proper divisors (11001926069).
82833444680131 is a wasteful number, since it uses less digits than its factorization.
82833444680131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11001926068.
The product of its (nonzero) digits is 10616832, while the sum is 55.
The spelling of 82833444680131 in words is "eighty-two trillion, eight hundred thirty-three billion, four hundred forty-four million, six hundred eighty thousand, one hundred thirty-one".
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