Base | Representation |
---|---|
bin | 10010110110011011110100… |
… | …000110001111111000010011 |
3 | 101212112200201121100201012011 |
4 | 102312123310012033320103 |
5 | 41331311033312313003 |
6 | 452154141415043351 |
7 | 23314504625623522 |
oct | 2266336406177023 |
9 | 355480647321164 |
10 | 82905554026003 |
11 | 244640589a4755 |
12 | 936b79a370557 |
13 | 3734c637310b7 |
14 | 16689163084b9 |
15 | 98b86c83546d |
hex | 4b66f418fe13 |
82905554026003 has 4 divisors (see below), whose sum is σ = 83124302190040. Its totient is φ = 82686805861968.
The previous prime is 82905554025901. The next prime is 82905554026037. The reversal of 82905554026003 is 30062045550928.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 82905554026003 - 217 = 82905553894931 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (82905554026303) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 109374081450 + ... + 109374082207.
It is an arithmetic number, because the mean of its divisors is an integer number (20781075547510).
Almost surely, 282905554026003 is an apocalyptic number.
82905554026003 is a deficient number, since it is larger than the sum of its proper divisors (218748164037).
82905554026003 is a wasteful number, since it uses less digits than its factorization.
82905554026003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 218748164036.
The product of its (nonzero) digits is 2592000, while the sum is 49.
The spelling of 82905554026003 in words is "eighty-two trillion, nine hundred five billion, five hundred fifty-four million, twenty-six thousand, three".
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