Base | Representation |
---|---|
bin | 10010111000101100111000… |
… | …001111101101000011010011 |
3 | 101220002120202221022212210111 |
4 | 102320230320033231003103 |
5 | 41341334033420200011 |
6 | 452353501502342151 |
7 | 23331660563233234 |
oct | 2270547017550323 |
9 | 356076687285714 |
10 | 83061316178131 |
11 | 2451411963aaa5 |
12 | 9395a0a88a957 |
13 | 37468579ccc15 |
14 | 167229107308b |
15 | 990937219121 |
hex | 4b8b383ed0d3 |
83061316178131 has 4 divisors (see below), whose sum is σ = 83074452562152. Its totient is φ = 83048179794112.
The previous prime is 83061316178117. The next prime is 83061316178143. The reversal of 83061316178131 is 13187161316038.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 83061316178131 - 237 = 82923877224659 is a prime.
It is a super-2 number, since 2×830613161781312 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (83061316178161) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6568182526 + ... + 6568195171.
It is an arithmetic number, because the mean of its divisors is an integer number (20768613140538).
Almost surely, 283061316178131 is an apocalyptic number.
83061316178131 is a deficient number, since it is larger than the sum of its proper divisors (13136384021).
83061316178131 is a wasteful number, since it uses less digits than its factorization.
83061316178131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13136384020.
The product of its (nonzero) digits is 435456, while the sum is 49.
The spelling of 83061316178131 in words is "eighty-three trillion, sixty-one billion, three hundred sixteen million, one hundred seventy-eight thousand, one hundred thirty-one".
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