Base | Representation |
---|---|
bin | 11000001011111101011… |
… | …01001101010000110001 |
3 | 2221110002121121011201111 |
4 | 30011332231031100301 |
5 | 102103444420440040 |
6 | 1433440421233321 |
7 | 114020206266016 |
oct | 14057655152061 |
9 | 2843077534644 |
10 | 831054468145 |
11 | 2a04a2644300 |
12 | 115092562841 |
13 | 604a293ca05 |
14 | 2c31a85970d |
15 | 1693e7aadea |
hex | c17eb4d431 |
831054468145 has 12 divisors (see below), whose sum is σ = 1096167712500. Its totient is φ = 604403249120.
The previous prime is 831054468121. The next prime is 831054468151. The reversal of 831054468145 is 541864450138.
831054468145 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It can be written as a sum of positive squares in 2 ways, for example, as 653032074816 + 178022393329 = 808104^2 + 421927^2 .
It is not a de Polignac number, because 831054468145 - 213 = 831054459953 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 686821270 + ... + 686822479.
It is an arithmetic number, because the mean of its divisors is an integer number (91347309375).
Almost surely, 2831054468145 is an apocalyptic number.
It is an amenable number.
831054468145 is a deficient number, since it is larger than the sum of its proper divisors (265113244355).
831054468145 is a wasteful number, since it uses less digits than its factorization.
831054468145 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1373643776 (or 1373643765 counting only the distinct ones).
The product of its (nonzero) digits is 1843200, while the sum is 49.
The spelling of 831054468145 in words is "eight hundred thirty-one billion, fifty-four million, four hundred sixty-eight thousand, one hundred forty-five".
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