Search a number
-
+
831300473 = 6831217131
BaseRepresentation
bin110001100011001…
…010001101111001
32010221020102212102
4301203022031321
53200303103343
6214253353145
726412636353
oct6143121571
92127212772
10831300473
1139727a393
121b24987b5
131032c1a93
147c5960d3
154ceab3b8
hex318ca379

831300473 has 4 divisors (see below), whose sum is σ = 832518288. Its totient is φ = 830082660.

The previous prime is 831300469. The next prime is 831300487. The reversal of 831300473 is 374003138.

831300473 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 831300473 - 22 = 831300469 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (831300413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 607883 + ... + 609248.

It is an arithmetic number, because the mean of its divisors is an integer number (208129572).

Almost surely, 2831300473 is an apocalyptic number.

It is an amenable number.

831300473 is a deficient number, since it is larger than the sum of its proper divisors (1217815).

831300473 is a wasteful number, since it uses less digits than its factorization.

831300473 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1217814.

The product of its (nonzero) digits is 6048, while the sum is 29.

The square root of 831300473 is about 28832.2817862201. The cubic root of 831300473 is about 940.2702078941.

The spelling of 831300473 in words is "eight hundred thirty-one million, three hundred thousand, four hundred seventy-three".

Divisors: 1 683 1217131 831300473