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83251013321 = 711893001903
BaseRepresentation
bin100110110001000100…
…1011010011011001001
321221212220110122212202
41031202021122123021
52330444224411241
6102124530045545
76005015636360
oct1154211323311
9257786418782
1083251013321
1132341032553
12141747198b5
137b09825038
14405a8427d7
152273ae6d9b
hex136225a6c9

83251013321 has 4 divisors (see below), whose sum is σ = 95144015232. Its totient is φ = 71358011412.

The previous prime is 83251013299. The next prime is 83251013341. The reversal of 83251013321 is 12331015238.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 83251013321 - 210 = 83251012297 is a prime.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (83251013341) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5946500945 + ... + 5946500958.

It is an arithmetic number, because the mean of its divisors is an integer number (23786003808).

Almost surely, 283251013321 is an apocalyptic number.

It is an amenable number.

83251013321 is a deficient number, since it is larger than the sum of its proper divisors (11893001911).

83251013321 is a wasteful number, since it uses less digits than its factorization.

83251013321 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11893001910.

The product of its (nonzero) digits is 4320, while the sum is 29.

Adding to 83251013321 its reverse (12331015238), we get a palindrome (95582028559).

The spelling of 83251013321 in words is "eighty-three billion, two hundred fifty-one million, thirteen thousand, three hundred twenty-one".

Divisors: 1 7 11893001903 83251013321