Base | Representation |
---|---|
bin | 10010111100111101000000… |
… | …100000010010010100100001 |
3 | 101221010111222121021221121022 |
4 | 102330331000200102110201 |
5 | 41411130443201101240 |
6 | 453140024112135225 |
7 | 23362043513162624 |
oct | 2274750040222441 |
9 | 357114877257538 |
10 | 83353512518945 |
11 | 24617031882689 |
12 | 9422576837515 |
13 | 3768282b912c6 |
14 | 168248da19dbb |
15 | 9983397629b5 |
hex | 4bcf40812521 |
83353512518945 has 4 divisors (see below), whose sum is σ = 100024215022740. Its totient is φ = 66682810015152.
The previous prime is 83353512518929. The next prime is 83353512518953. The reversal of 83353512518945 is 54981521535338.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 47603265838144 + 35750246680801 = 6899512^2 + 5979151^2 .
It is a cyclic number.
It is not a de Polignac number, because 83353512518945 - 24 = 83353512518929 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8335351251890 + ... + 8335351251899.
It is an arithmetic number, because the mean of its divisors is an integer number (25006053755685).
Almost surely, 283353512518945 is an apocalyptic number.
It is an amenable number.
83353512518945 is a deficient number, since it is larger than the sum of its proper divisors (16670702503795).
83353512518945 is a wasteful number, since it uses less digits than its factorization.
83353512518945 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16670702503794.
The product of its digits is 77760000, while the sum is 62.
The spelling of 83353512518945 in words is "eighty-three trillion, three hundred fifty-three billion, five hundred twelve million, five hundred eighteen thousand, nine hundred forty-five".
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