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83365812051 = 327788604017
BaseRepresentation
bin100110110100011111…
…1010101011101010011
321222011220111001010120
41031220333111131103
52331213121441201
6102144150401323
76010611465504
oct1155077253523
9258156431116
1083365812051
113239a911535
12141a7060243
137b2754a692
14406bba6bab
15227dc21536
hex1368fd5753

83365812051 has 4 divisors (see below), whose sum is σ = 111154416072. Its totient is φ = 55577208032.

The previous prime is 83365812043. The next prime is 83365812071. The reversal of 83365812051 is 15021856338.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 83365812051 - 23 = 83365812043 is a prime.

It is a super-3 number, since 3×833658120513 (a number of 34 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 83365811994 and 83365812012.

It is not an unprimeable number, because it can be changed into a prime (83365812041) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13894302006 + ... + 13894302011.

It is an arithmetic number, because the mean of its divisors is an integer number (27788604018).

Almost surely, 283365812051 is an apocalyptic number.

83365812051 is a deficient number, since it is larger than the sum of its proper divisors (27788604021).

83365812051 is a wasteful number, since it uses less digits than its factorization.

83365812051 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 27788604020.

The product of its (nonzero) digits is 172800, while the sum is 42.

The spelling of 83365812051 in words is "eighty-three billion, three hundred sixty-five million, eight hundred twelve thousand, fifty-one".

Divisors: 1 3 27788604017 83365812051