8512693972153 has 4 divisors (see below), whose sum is σ = 9728793111040. Its totient is φ = 7296594833268.

The previous prime is 8512693972049. The next prime is 8512693972163. The reversal of 8512693972153 is 3512793962158.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 8512693972153 - 2⁹ = 8512693971641 is a prime.

It is a super-2 number, since 2×8512693972153² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 8512693972091 and 8512693972100.

It is not an unprimeable number, because it can be changed into a prime (8512693972163) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 608049569433 + ... + 608049569446.

It is an arithmetic number, because the mean of its divisors is an integer number (2432198277760).

Almost surely, 2^{8512693972153} is an apocalyptic number.

It is an amenable number.

8512693972153 is a deficient number, since it is larger than the sum of its proper divisors (1216099138887).

8512693972153 is a wasteful number, since it uses less digits than its factorization.

8512693972153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1216099138886.

The product of its digits is 24494400, while the sum is 61.

The spelling of 8512693972153 in words is "eight trillion, five hundred twelve billion, six hundred ninety-three million, nine hundred seventy-two thousand, one hundred fifty-three".