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85439845121 = 475917953319
BaseRepresentation
bin100111110010010011…
…1001001001100000001
322011112110010211122012
41033210213021030001
52344440100020441
6103130040222305
76113164462241
oct1174447111401
9264473124565
1085439845121
1133264624254
121468576a995
138098146197
1441c7413b21
152350d599eb
hex13e49c9301

85439845121 has 4 divisors (see below), whose sum is σ = 85457803200. Its totient is φ = 85421887044.

The previous prime is 85439845103. The next prime is 85439845181. The reversal of 85439845121 is 12154893458.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 85439845121 - 226 = 85372736257 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 85439845121.

It is not an unprimeable number, because it can be changed into a prime (85439845181) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8971901 + ... + 8981418.

It is an arithmetic number, because the mean of its divisors is an integer number (21364450800).

Almost surely, 285439845121 is an apocalyptic number.

It is an amenable number.

85439845121 is a deficient number, since it is larger than the sum of its proper divisors (17958079).

85439845121 is a wasteful number, since it uses less digits than its factorization.

85439845121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 17958078.

The product of its digits is 1382400, while the sum is 50.

The spelling of 85439845121 in words is "eighty-five billion, four hundred thirty-nine million, eight hundred forty-five thousand, one hundred twenty-one".

Divisors: 1 4759 17953319 85439845121