Base | Representation |
---|---|
bin | 100111110011101010… |
… | …0111101000101101001 |
3 | 22011122121212201000002 |
4 | 1033213110331011221 |
5 | 2400033231033432 |
6 | 103134344552345 |
7 | 6114256661360 |
oct | 1174724750551 |
9 | 264577781002 |
10 | 85485408617 |
11 | 33288314834 |
12 | 14698a826b5 |
13 | 80a470a12b |
14 | 41cd4b47d7 |
15 | 2354d59e62 |
hex | 13e753d169 |
85485408617 has 4 divisors (see below), whose sum is σ = 97697609856. Its totient is φ = 73273207380.
The previous prime is 85485408553. The next prime is 85485408623. The reversal of 85485408617 is 71680458458.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 85485408617 - 26 = 85485408553 is a prime.
It is a super-3 number, since 3×854854086173 (a number of 34 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (85485428617) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6106100609 + ... + 6106100622.
It is an arithmetic number, because the mean of its divisors is an integer number (24424402464).
Almost surely, 285485408617 is an apocalyptic number.
It is an amenable number.
85485408617 is a deficient number, since it is larger than the sum of its proper divisors (12212201239).
85485408617 is a wasteful number, since it uses less digits than its factorization.
85485408617 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 12212201238.
The product of its (nonzero) digits is 8601600, while the sum is 56.
The spelling of 85485408617 in words is "eighty-five billion, four hundred eighty-five million, four hundred eight thousand, six hundred seventeen".
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