Base | Representation |
---|---|
bin | 10100011100011011001111… |
… | …000111001101101111101011 |
3 | 102210100201120120022220022102 |
4 | 110130123033013031233223 |
5 | 43241124011424240413 |
6 | 515122022441044015 |
7 | 24640044446665244 |
oct | 2434331707155753 |
9 | 383321516286272 |
10 | 89914320149483 |
11 | 267164a3732345 |
12 | a101bb7a8660b |
13 | 3b22b6522112b |
14 | 182bc3a875ccb |
15 | a5dd27914458 |
hex | 51c6cf1cdbeb |
89914320149483 has 4 divisors (see below), whose sum is σ = 89914367268000. Its totient is φ = 89914273030968.
The previous prime is 89914320149369. The next prime is 89914320149539. The reversal of 89914320149483 is 38494102341998.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 89914320149483 - 222 = 89914315955179 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (89914320149183) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20570483 + ... + 24555516.
It is an arithmetic number, because the mean of its divisors is an integer number (22478591817000).
Almost surely, 289914320149483 is an apocalyptic number.
89914320149483 is a deficient number, since it is larger than the sum of its proper divisors (47118517).
89914320149483 is a wasteful number, since it uses less digits than its factorization.
89914320149483 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 47118516.
The product of its (nonzero) digits is 53747712, while the sum is 65.
The spelling of 89914320149483 in words is "eighty-nine trillion, nine hundred fourteen billion, three hundred twenty million, one hundred forty-nine thousand, four hundred eighty-three".
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