935313140473 has 4 divisors (see below), whose sum is σ = 949273038160. Its totient is φ = 921353242788.

The previous prime is 935313140441. The next prime is 935313140479. The reversal of 935313140473 is 374041313539.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 935313140473 - 2⁵ = 935313140441 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (935313140479) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6979948743 + ... + 6979948876.

It is an arithmetic number, because the mean of its divisors is an integer number (237318259540).

Almost surely, 2^935313140473 is an apocalyptic number.

It is an amenable number.

935313140473 is a deficient number, since it is larger than the sum of its proper divisors (13959897687).

935313140473 is a wasteful number, since it uses less digits than its factorization.

935313140473 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13959897686.

The product of its (nonzero) digits is 408240, while the sum is 43.

The spelling of 935313140473 in words is "nine hundred thirty-five billion, three hundred thirteen million, one hundred forty thousand, four hundred seventy-three".