94401981403 has 8 divisors (see below), whose sum is σ = 99491559120. Its totient is φ = 89324508960.

The previous prime is 94401981367. The next prime is 94401981407. The reversal of 94401981403 is 30418910449.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 94401981403 - 2¹⁷ = 94401850331 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 94401981403.

It is not an unprimeable number, because it can be changed into a prime (94401981407) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3010300 + ... + 3041497.

It is an arithmetic number, because the mean of its divisors is an integer number (12436444890).

Almost surely, 2^94401981403 is an apocalyptic number.

94401981403 is a deficient number, since it is larger than the sum of its proper divisors (5089577717).

94401981403 is a wasteful number, since it uses less digits than its factorization.

94401981403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6052637.

The product of its (nonzero) digits is 124416, while the sum is 43.

The spelling of 94401981403 in words is "ninety-four billion, four hundred one million, nine hundred eighty-one thousand, four hundred three".