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95118911953 = 137316839381
BaseRepresentation
bin101100010010110000…
…1110110100111010001
3100002112000000101012221
41120211201312213101
53024300420140303
6111410320221041
76605064261052
oct1304541664721
9302460011187
1095118911953
113738116743a
121652716a781
138c7b4b6770
144864ab4729
15271a9714bd
hex16258769d1

95118911953 has 4 divisors (see below), whose sum is σ = 102435751348. Its totient is φ = 87802072560.

The previous prime is 95118911933. The next prime is 95118911959. The reversal of 95118911953 is 35911981159.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 47946547089 + 47172364864 = 218967^2 + 217192^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-95118911953 is a prime.

It is a super-2 number, since 2×951189119532 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 95118911953.

It is not an unprimeable number, because it can be changed into a prime (95118911959) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3658419678 + ... + 3658419703.

It is an arithmetic number, because the mean of its divisors is an integer number (25608937837).

Almost surely, 295118911953 is an apocalyptic number.

It is an amenable number.

95118911953 is a deficient number, since it is larger than the sum of its proper divisors (7316839395).

95118911953 is a wasteful number, since it uses less digits than its factorization.

95118911953 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7316839394.

The product of its digits is 437400, while the sum is 52.

The spelling of 95118911953 in words is "ninety-five billion, one hundred eighteen million, nine hundred eleven thousand, nine hundred fifty-three".

Divisors: 1 13 7316839381 95118911953