Base | Representation |
---|---|
bin | 1000101011100000000001… |
… | …0110011001101111011001 |
3 | 1020210100020120102212121021 |
4 | 2022320000112121233121 |
5 | 2222324412320014223 |
6 | 32144104343442441 |
7 | 2003326631536135 |
oct | 212700026315731 |
9 | 36710216385537 |
10 | 9543423204313 |
11 | 304a385669739 |
12 | 10a16b5156421 |
13 | 542c3034b8ab |
14 | 24dc92da43c5 |
15 | 1183a65d465d |
hex | 8ae00599bd9 |
9543423204313 has 4 divisors (see below), whose sum is σ = 9543504309120. Its totient is φ = 9543342099508.
The previous prime is 9543423204311. The next prime is 9543423204331. The reversal of 9543423204313 is 3134023243459.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 9543423204313 - 21 = 9543423204311 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 9543423204313.
It is not an unprimeable number, because it can be changed into a prime (9543423204311) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 40375645 + ... + 40611322.
It is an arithmetic number, because the mean of its divisors is an integer number (2385876077280).
Almost surely, 29543423204313 is an apocalyptic number.
It is an amenable number.
9543423204313 is a deficient number, since it is larger than the sum of its proper divisors (81104807).
9543423204313 is a wasteful number, since it uses less digits than its factorization.
9543423204313 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 81104806.
The product of its (nonzero) digits is 933120, while the sum is 43.
The spelling of 9543423204313 in words is "nine trillion, five hundred forty-three billion, four hundred twenty-three million, two hundred four thousand, three hundred thirteen".
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