95501000993 has 4 divisors (see below), whose sum is σ = 95501742768. Its totient is φ = 95500259220.

The previous prime is 95501000989. The next prime is 95501001017. The reversal of 95501000993 is 39900010559.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 39900010559 = 499 ⋅79959941.

It is a cyclic number.

It is not a de Polignac number, because 95501000993 - 2² = 95501000989 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 95501000993.

It is not an unprimeable number, because it can be changed into a prime (95501000983) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 122171 + ... + 453792.

It is an arithmetic number, because the mean of its divisors is an integer number (23875435692).

Almost surely, 2^95501000993 is an apocalyptic number.

It is an amenable number.

95501000993 is a deficient number, since it is larger than the sum of its proper divisors (741775).

95501000993 is a wasteful number, since it uses less digits than its factorization.

95501000993 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 741774.

The product of its (nonzero) digits is 54675, while the sum is 41.

The spelling of 95501000993 in words is "ninety-five billion, five hundred one million, nine hundred ninety-three", and thus it is an aban number.