Base | Representation |
---|---|
bin | 101100101101001010… |
… | …0000110011111101001 |
3 | 100011210201101212212020 |
4 | 1121122110012133221 |
5 | 3033104122440213 |
6 | 112034233335053 |
7 | 6636036531543 |
oct | 1313224063751 |
9 | 304721355766 |
10 | 96004499433 |
11 | 37796045417 |
12 | 16733867489 |
13 | 908cb0501b |
14 | 490a55c693 |
15 | 276d5a2923 |
hex | 165a5067e9 |
96004499433 has 16 divisors (see below), whose sum is σ = 135761179776. Its totient is φ = 60216647040.
The previous prime is 96004499389. The next prime is 96004499443. The reversal of 96004499433 is 33499440069.
It is not a de Polignac number, because 96004499433 - 229 = 95467628521 is a prime.
It is a super-2 number, since 2×960044994332 (a number of 23 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (96004499443) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 11400460 + ... + 11408877.
It is an arithmetic number, because the mean of its divisors is an integer number (8485073736).
Almost surely, 296004499433 is an apocalyptic number.
It is an amenable number.
96004499433 is a deficient number, since it is larger than the sum of its proper divisors (39756680343).
96004499433 is a wasteful number, since it uses less digits than its factorization.
96004499433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 22809424.
The product of its (nonzero) digits is 2519424, while the sum is 51.
The spelling of 96004499433 in words is "ninety-six billion, four million, four hundred ninety-nine thousand, four hundred thirty-three".
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