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96994355513 = 118817668683
BaseRepresentation
bin101101001010101010…
…0000110100100111001
3100021100200222210010112
41122111110012210321
53042121023334023
6112320353354105
710002416263406
oct1322524064471
9307320883115
1096994355513
113815386a9a0
121696b268935
1391b9bccc93
1449a1bc92ad
1527ca42d478
hex1695506939

96994355513 has 4 divisors (see below), whose sum is σ = 105812024208. Its totient is φ = 88176686820.

The previous prime is 96994355483. The next prime is 96994355533. The reversal of 96994355513 is 31555349969.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 96994355513 - 214 = 96994339129 is a prime.

It is not an unprimeable number, because it can be changed into a prime (96994355533) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4408834331 + ... + 4408834352.

It is an arithmetic number, because the mean of its divisors is an integer number (26453006052).

Almost surely, 296994355513 is an apocalyptic number.

It is an amenable number.

96994355513 is a deficient number, since it is larger than the sum of its proper divisors (8817668695).

96994355513 is a wasteful number, since it uses less digits than its factorization.

96994355513 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8817668694.

The product of its digits is 19683000, while the sum is 59.

The spelling of 96994355513 in words is "ninety-six billion, nine hundred ninety-four million, three hundred fifty-five thousand, five hundred thirteen".

Divisors: 1 11 8817668683 96994355513