Base | Representation |
---|---|
bin | 101101101001101001… |
… | …1011110101010001011 |
3 | 100101001011222110200212 |
4 | 1123103103132222023 |
5 | 3101233300120103 |
6 | 113011504551335 |
7 | 10040245322132 |
oct | 1332323365213 |
9 | 311034873625 |
10 | 98034379403 |
11 | 38637940274 |
12 | 16bbb62254b |
13 | 932451182c |
14 | 4a5dd94919 |
15 | 283b8b87d8 |
hex | 16d34dea8b |
98034379403 has 4 divisors (see below), whose sum is σ = 98182692288. Its totient is φ = 97886066520.
The previous prime is 98034379393. The next prime is 98034379433. The reversal of 98034379403 is 30497343089.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 98034379403 - 214 = 98034363019 is a prime.
It is a super-2 number, since 2×980343794032 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (98034379433) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 74155451 + ... + 74156772.
It is an arithmetic number, because the mean of its divisors is an integer number (24545673072).
Almost surely, 298034379403 is an apocalyptic number.
98034379403 is a deficient number, since it is larger than the sum of its proper divisors (148312885).
98034379403 is a wasteful number, since it uses less digits than its factorization.
98034379403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 148312884.
The product of its (nonzero) digits is 1959552, while the sum is 50.
The spelling of 98034379403 in words is "ninety-eight billion, thirty-four million, three hundred seventy-nine thousand, four hundred three".
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