Base | Representation |
---|---|
bin | 10110010011101111010110… |
… | …111001011001111010100001 |
3 | 110212101120012112020201020111 |
4 | 112103233112321121322201 |
5 | 100324443014042040410 |
6 | 544400423425011321 |
7 | 26444320031660323 |
oct | 2623572671317241 |
9 | 425346175221214 |
10 | 98113543315105 |
11 | 292977a142859a |
12 | b00708b183b41 |
13 | 42990b5202836 |
14 | 1a32a13d7b613 |
15 | b52259a00b8a |
hex | 593bd6e59ea1 |
98113543315105 has 16 divisors (see below), whose sum is σ = 123953072209920. Its totient is φ = 74347632857088.
The previous prime is 98113543315061. The next prime is 98113543315169. The reversal of 98113543315105 is 50151334531189.
It is a cyclic number.
It is not a de Polignac number, because 98113543315105 - 213 = 98113543306913 is a prime.
It is a super-2 number, since 2×981135433151052 (a number of 29 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 83477472 + ... + 84644641.
It is an arithmetic number, because the mean of its divisors is an integer number (7747067013120).
Almost surely, 298113543315105 is an apocalyptic number.
98113543315105 is a gapful number since it is divisible by the number (95) formed by its first and last digit.
It is an amenable number.
98113543315105 is a deficient number, since it is larger than the sum of its proper divisors (25839528894815).
98113543315105 is a wasteful number, since it uses less digits than its factorization.
98113543315105 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 168128280.
The product of its (nonzero) digits is 972000, while the sum is 49.
The spelling of 98113543315105 in words is "ninety-eight trillion, one hundred thirteen billion, five hundred forty-three million, three hundred fifteen thousand, one hundred five".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.086 sec. • engine limits •