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98164230075 = 3552171922633
BaseRepresentation
bin101101101101100001…
…0110100011110111011
3100101101020022120100000
41123123002310132323
53102020020330300
6113032424044043
710043413121412
oct1333302643673
9311336276300
1098164230075
11386a416aa7a
1217037003623
1393453a7352
144a73316479
152847eb7c00
hex16db0b47bb

98164230075 has 216 divisors, whose sum is σ = 203833860048. Its totient is φ = 46663464960.

The previous prime is 98164230029. The next prime is 98164230083. The reversal of 98164230075 is 57003246189.

It is not a de Polignac number, because 98164230075 - 218 = 98163967931 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (45).

It is a self number, because there is not a number n which added to its sum of digits gives 98164230075.

It is an unprimeable number.

It is a polite number, since it can be written in 215 ways as a sum of consecutive naturals, for example, 37280959 + ... + 37283591.

It is an arithmetic number, because the mean of its divisors is an integer number (943675278).

It is a 1-persistent number, because it is pandigital, but 2⋅98164230075 = 196328460150 is not.

Almost surely, 298164230075 is an apocalyptic number.

98164230075 is a gapful number since it is divisible by the number (95) formed by its first and last digit.

98164230075 is an abundant number, since it is smaller than the sum of its proper divisors (105669629973).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

98164230075 is a wasteful number, since it uses less digits than its factorization.

98164230075 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2713 (or 2677 counting only the distinct ones).

The product of its (nonzero) digits is 362880, while the sum is 45.

The spelling of 98164230075 in words is "ninety-eight billion, one hundred sixty-four million, two hundred thirty thousand, seventy-five".