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98483263897 = 234281881039
BaseRepresentation
bin101101110111000001…
…1110101100110011001
3100102012110122011110111
41123232003311212121
53103143203421042
6113124222044321
710054335634234
oct1335603654631
9312173564414
1098483263897
1138848264897
1217105a196a1
13939650a865
144aa384241b
152865ed6517
hex16ee0f5999

98483263897 has 4 divisors (see below), whose sum is σ = 102765144960. Its totient is φ = 94201382836.

The previous prime is 98483263891. The next prime is 98483263981. The reversal of 98483263897 is 79836238489.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 98483263897 - 231 = 96335780249 is a prime.

It is a super-2 number, since 2×984832638972 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (98483263891) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2140940497 + ... + 2140940542.

It is an arithmetic number, because the mean of its divisors is an integer number (25691286240).

Almost surely, 298483263897 is an apocalyptic number.

It is an amenable number.

98483263897 is a deficient number, since it is larger than the sum of its proper divisors (4281881063).

98483263897 is a wasteful number, since it uses less digits than its factorization.

98483263897 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4281881062.

The product of its digits is 125411328, while the sum is 67.

The spelling of 98483263897 in words is "ninety-eight billion, four hundred eighty-three million, two hundred sixty-three thousand, eight hundred ninety-seven".

Divisors: 1 23 4281881039 98483263897