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99100639873 = 127780319999
BaseRepresentation
bin101110001001011011…
…0111100001010000001
3100110210111100010002101
41130102312330022001
53110424230433443
6113305354350401
710105543353214
oct1342266741201
9313714303071
1099100639873
1139034800574
121725872b401
1394643ab3a1
144b2182d77b
1528a02d784d
hex1712dbc281

99100639873 has 4 divisors (see below), whose sum is σ = 99880960000. Its totient is φ = 98320319748.

The previous prime is 99100639871. The next prime is 99100639889. The reversal of 99100639873 is 37893600199.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 99100639873 - 21 = 99100639871 is a prime.

It is a super-2 number, since 2×991006398732 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (99100639871) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 390159873 + ... + 390160126.

It is an arithmetic number, because the mean of its divisors is an integer number (24970240000).

Almost surely, 299100639873 is an apocalyptic number.

It is an amenable number.

99100639873 is a deficient number, since it is larger than the sum of its proper divisors (780320127).

99100639873 is a wasteful number, since it uses less digits than its factorization.

99100639873 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 780320126.

The product of its (nonzero) digits is 2204496, while the sum is 55.

The spelling of 99100639873 in words is "ninety-nine billion, one hundred million, six hundred thirty-nine thousand, eight hundred seventy-three".

Divisors: 1 127 780319999 99100639873