Base | Representation |
---|---|
bin | 101110010000000111… |
… | …1010100111000010011 |
3 | 100111101010202201102200 |
4 | 1130200033110320103 |
5 | 3111404213331103 |
6 | 113343534214243 |
7 | 10114240505103 |
oct | 1344017247023 |
9 | 314333681380 |
10 | 99325136403 |
11 | 3913a4a5099 |
12 | 172bb954383 |
13 | 949ba6167c |
14 | 4b4358b203 |
15 | 28b4d800a3 |
hex | 17203d4e13 |
99325136403 has 12 divisors (see below), whose sum is σ = 143478075000. Its totient is φ = 66212865216.
The previous prime is 99325136401. The next prime is 99325136467. The reversal of 99325136403 is 30463152399.
99325136403 is a `hidden beast` number, since 9 + 93 + 2 + 513 + 6 + 40 + 3 = 666.
It is not a de Polignac number, because 99325136403 - 21 = 99325136401 is a prime.
It is not an unprimeable number, because it can be changed into a prime (99325136401) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 158278 + ... + 472971.
It is an arithmetic number, because the mean of its divisors is an integer number (11956506250).
Almost surely, 299325136403 is an apocalyptic number.
99325136403 is a deficient number, since it is larger than the sum of its proper divisors (44152938597).
99325136403 is a wasteful number, since it uses less digits than its factorization.
99325136403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 648738 (or 648735 counting only the distinct ones).
The product of its (nonzero) digits is 524880, while the sum is 45.
The spelling of 99325136403 in words is "ninety-nine billion, three hundred twenty-five million, one hundred thirty-six thousand, four hundred three".
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