Base | Representation |
---|---|
bin | 10110100110111100010100… |
… | …100101110111110110110011 |
3 | 111001001201022000200122112011 |
4 | 112212330110211313312303 |
5 | 101013103024113422011 |
6 | 551250541214543351 |
7 | 26641543511066311 |
oct | 2646742445676663 |
9 | 431051260618464 |
10 | 99433133342131 |
11 | 2975639a611a66 |
12 | b19a983207b57 |
13 | 4363672a80b34 |
14 | 1a7a8371ad0b1 |
15 | b7673d6ad621 |
hex | 5a6f14977db3 |
99433133342131 has 4 divisors (see below), whose sum is σ = 101745531791992. Its totient is φ = 97120734892272.
The previous prime is 99433133342111. The next prime is 99433133342141. The reversal of 99433133342131 is 13124333133499.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 99433133342131 - 213 = 99433133333939 is a prime.
It is a super-2 number, since 2×994331333421312 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (99433133342111) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1156199224866 + ... + 1156199224951.
It is an arithmetic number, because the mean of its divisors is an integer number (25436382947998).
Almost surely, 299433133342131 is an apocalyptic number.
99433133342131 is a deficient number, since it is larger than the sum of its proper divisors (2312398449861).
99433133342131 is a wasteful number, since it uses less digits than its factorization.
99433133342131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2312398449860.
The product of its digits is 1889568, while the sum is 49.
The spelling of 99433133342131 in words is "ninety-nine trillion, four hundred thirty-three billion, one hundred thirty-three million, three hundred forty-two thousand, one hundred thirty-one".
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